What is the answer to (1/6)^x=9 ?

The answer to (1/6)^x=9 is x=-(2ln(3))/(ln(6))

Solve for x: (1/6)^x=9

The solution is x=-(2ln(3))/(ln(6))

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(\frac{1}{6})^{x} = 9

x = - \frac{2 ln ( 3 )}{ln ( 6 )}

Decimal Notation

x = - 1.22629 \dots

Solution steps

(\frac{1}{6})^{x} = 9

Apply exponent rules

x ln (\frac{1}{6}) = ln (9)

Solve

x ln (\frac{1}{6}) = ln (9) : x = - \frac{2 ln ( 3 )}{ln ( 6 )}

x = - \frac{2 ln ( 3 )}{ln ( 6 )}

4 \cdot 1 0^{2 x} + 1 = 21

x, e^{l n (x)} = e^{y + c}

2 (4^{2 x + 1}) = 128

3^{x} = \frac{1}{4}

2^{- 3 x + 1} = \frac{1}{16}

What is the answer to (1/6)^x=9 ?
The answer to (1/6)^x=9 is x=-(2ln(3))/(ln(6))
Solve for x: (1/6)^x=9
The solution is x=-(2ln(3))/(ln(6))