What is the answer to 4^x=\sqrt[5]{32} ?

The answer to 4^x=\sqrt[5]{32} is x= 1/2

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4^x=\sqrt[5]{32}

x = \frac{1}{2}

Decimal Notation

x = 0.5

Solution steps

Apply exponent rules

2 x = 1

Solve

2 x = 1 : x = \frac{1}{2}

x = \frac{1}{2}

- 3 e^{9 x - 1} + 6 = - 58

625 = 5^{5 x + 1}

(x + 5) e^{\frac{1}{x - 1}} = 0

(x - 3)^{x^{2} + 1} = (x - 3)^{3 x + 11}

10 e^{2 x} = 7 \cdot 2^{a x}

What is the answer to 4^x=\sqrt[5]{32} ?
The answer to 4^x=\sqrt[5]{32} is x= 1/2
Solve for x: 4^x=\sqrt[5]{32}
The solution is x= 1/2