What is the answer to 4^{2x-1}+4^{2x}=4 ?

The answer to 4^{2x-1}+4^{2x}=4 is x=(ln(16/5))/(4ln(2))

Solve for x: 4^{2x-1}+4^{2x}=4

The solution is x=(ln(16/5))/(4ln(2))

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4^{2 x - 1} + 4^{2 x} = 4

x = \frac{ln ( \frac{16}{5} )}{4 ln ( 2 )}

Decimal Notation

x = 0.41951 \dots

Solution steps

4^{2 x - 1} + 4^{2 x} = 4

Apply exponent rules

2 x ln (4) = ln (\frac{16}{5})

Solve

2 x ln (4) = ln (\frac{16}{5}) : x = \frac{ln ( \frac{16}{5} )}{4 ln ( 2 )}

x = \frac{ln ( \frac{16}{5} )}{4 ln ( 2 )}

3 2^{2 x + 3} = 1 6^{x + 4}

3 (2^{2 x + 3}) - 43 (2^{x}) + 5 = 0

2^{2 x + 2} + 2^{x + 2} = 3

2 e^{3 x} = 32

9^{x + 1} + 1 = 10 (3 x)

What is the answer to 4^{2x-1}+4^{2x}=4 ?
The answer to 4^{2x-1}+4^{2x}=4 is x=(ln(16/5))/(4ln(2))
Solve for x: 4^{2x-1}+4^{2x}=4
The solution is x=(ln(16/5))/(4ln(2))