What is the answer to 7(3^x)=2(4^{(5x-4)}) ?

The answer to 7(3^x)=2(4^{(5x-4)}) is x=(ln(896))/(10ln(2)-ln(3))

Solve for x: 7(3^x)=2(4^{(5x-4)})

The solution is x=(ln(896))/(10ln(2)-ln(3))

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7 (3^{x}) = 2 (4^{(5 x - 4)})

x = \frac{ln ( 896 )}{10 ln ( 2 ) - ln ( 3 )}

Decimal Notation

x = 1.16545 \dots

Solution steps

7 (3^{x}) = 2 (4^{(5 x - 4)})

Apply exponent rules

ln (7) + x ln (3) = ln (2) + (5 x - 4) ln (4)

Solve

ln (7) + x ln (3) = ln (2) + (5 x - 4) ln (4) : x = \frac{ln ( 896 )}{10 ln ( 2 ) - ln ( 3 )}

x = \frac{ln ( 896 )}{10 ln ( 2 ) - ln ( 3 )}

e^{x} - 6 x = 0

3 e^{x} - 4 x e^{x} = 0

3 \cdot 1 0^{- 9} = 1 0^{- x}

- e^{x + 4} = - 58

3^{n} = 3 \cdot 9^{3} \cdot 8 1^{2}

What is the answer to 7(3^x)=2(4^{(5x-4)}) ?
The answer to 7(3^x)=2(4^{(5x-4)}) is x=(ln(896))/(10ln(2)-ln(3))
Solve for x: 7(3^x)=2(4^{(5x-4)})
The solution is x=(ln(896))/(10ln(2)-ln(3))