What is the answer to 4^{6x+3}=32^{x(5-x)} ?

The answer to 4^{6x+3}=32^{x(5-x)} is x= 3/5 ,x=2

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4^{6x+3}=32^{x(5-x)}

4^{6 x + 3} = 3 2^{x (5 - x)}

x = \frac{3}{5}, x = 2

Decimal Notation

x = 0.6, x = 2

Solution steps

4^{6 x + 3} = 3 2^{x (5 - x)}

Apply exponent rules

2 (6 x + 3) = 5 x (5 - x)

Solve

2 (6 x + 3) = 5 x (5 - x) : x = \frac{3}{5}, x = 2

x = \frac{3}{5}, x = 2

7^{2 x} - 11 (7^{x}) + 10 = 0

3 \cdot 4^{x} + 4^{x - 1} = 208

2 7^{3 x} = 81

3^{x} mod 17 = 12

5^{x - 3} = 8

What is the answer to 4^{6x+3}=32^{x(5-x)} ?
The answer to 4^{6x+3}=32^{x(5-x)} is x= 3/5 ,x=2
Solve for x: 4^{6x+3}=32^{x(5-x)}
The solution is x= 3/5 ,x=2