What is the answer to 3*4^x+4^{x-1}=208 ?

The answer to 3*4^x+4^{x-1}=208 is x=3

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3*4^x+4^{x-1}=208

3 \cdot 4^{x} + 4^{x - 1} = 208

x = 3

Solution steps

3 \cdot 4^{x} + 4^{x - 1} = 208

Factor

3 \cdot 4^{x} + 4^{x - 1} : 13 \cdot 4^{x - 1}

13 \cdot 4^{x - 1} = 208

Divide both sides by

13

4^{x - 1} = 16

Apply exponent rules

x - 1 = 2

Solve

x - 1 = 2 : x = 3

x = 3

2 7^{3 x} = 81

3^{x} mod 17 = 12

5^{x - 3} = 8

3^{x + 2} = 9^{2 x - 1}

What is the answer to 3*4^x+4^{x-1}=208 ?
The answer to 3*4^x+4^{x-1}=208 is x=3
Solve for x: 3*4^x+4^{x-1}=208
The solution is x=3