What is the answer to 16*4^{x-2}=8^{x^2-x} ?

The answer to 16*4^{x-2}=8^{x^2-x} is x= 5/3 ,x=0

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16*4^{x-2}=8^{x^2-x}

16 \cdot 4^{x - 2} = 8^{x^{2} - x}

x = \frac{5}{3}, x = 0

Decimal Notation

x = 1.66666 \dots, x = 0

Solution steps

16 \cdot 4^{x - 2} = 8^{x^{2} - x}

Apply exponent rules

2 (x - 2) + 4 = 3 (x^{2} - x)

Solve

2 (x - 2) + 4 = 3 (x^{2} - x) : x = \frac{5}{3}, x = 0

x = \frac{5}{3}, x = 0

4 (1.2)^{x} = 36

e^{3 x + 2} = 1

2^{x + 1} = 256

3 6^{2 x + 1} = 6^{x - 3}

6 e^{- 7 x} = 2

What is the answer to 16*4^{x-2}=8^{x^2-x} ?
The answer to 16*4^{x-2}=8^{x^2-x} is x= 5/3 ,x=0
Solve for x: 16*4^{x-2}=8^{x^2-x}
The solution is x= 5/3 ,x=0