What is the answer to 36^{2x+1}=6^{x-3} ?

The answer to 36^{2x+1}=6^{x-3} is x=-5/3

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36^{2x+1}=6^{x-3}

3 6^{2 x + 1} = 6^{x - 3}

x = - \frac{5}{3}

Decimal Notation

x = - 1.66666 \dots

Solution steps

3 6^{2 x + 1} = 6^{x - 3}

Apply exponent rules

2 (2 x + 1) = x - 3

Solve

2 (2 x + 1) = x - 3 : x = - \frac{5}{3}

x = - \frac{5}{3}

6 e^{- 7 x} = 2

6 4^{x} = \frac{1}{2}

5^{3 x + 2} = 40

2^{(3 x^{3} + 11 x^{2} - 4 x)} = 1

3^{x - 2} - 3^{x + 1} + 78 = 0

What is the answer to 36^{2x+1}=6^{x-3} ?
The answer to 36^{2x+1}=6^{x-3} is x=-5/3
Solve for x: 36^{2x+1}=6^{x-3}
The solution is x=-5/3