What is the answer to 2^{(3x^3+11x^2-4x)}=1 ?

The answer to 2^{(3x^3+11x^2-4x)}=1 is x=0,x= 1/3 ,x=-4

Solve for x: 2^{(3x^3+11x^2-4x)}=1

The solution is x=0,x= 1/3 ,x=-4

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2^{(3 x^{3} + 11 x^{2} - 4 x)} = 1

x = 0, x = \frac{1}{3}, x = - 4

Decimal Notation

x = 0, x = 0.33333 \dots, x = - 4

Solution steps

2^{(3 x^{3} + 11 x^{2} - 4 x)} = 1

Apply exponent rules

(3 x^{3} + 11 x^{2} - 4 x) ln (2) = ln (1)

Solve

(3 x^{3} + 11 x^{2} - 4 x) ln (2) = ln (1) : x = 0, x = \frac{1}{3}, x = - 4

x = 0, x = \frac{1}{3}, x = - 4

3^{x - 2} - 3^{x + 1} + 78 = 0

8^{x} \cdot 4^{2 x - 1} = 32

5 e^{2 x} = 19

n, (1 - 0.01)^{n} = 0.01

4 \cdot 5^{x} - 3 = 7

What is the answer to 2^{(3x^3+11x^2-4x)}=1 ?
The answer to 2^{(3x^3+11x^2-4x)}=1 is x=0,x= 1/3 ,x=-4
Solve for x: 2^{(3x^3+11x^2-4x)}=1
The solution is x=0,x= 1/3 ,x=-4