What is the answer to solvefor n,(1-0.01)^n=0.01 ?

The answer to solvefor n,(1-0.01)^n=0.01 is n=(ln(0.01))/(ln(0.99))

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solvefor n,(1-0.01)^n=0.01

solve for

n, (1 - 0.01)^{n} = 0.01

n = \frac{ln ( 0.01 )}{ln ( 0.99 )}

Decimal Notation

n = 458.21057 \dots

Solution steps

(1 - 0.01)^{n} = 0.01

Apply exponent rules

n ln (1 - 0.01) = ln (0.01)

Solve

n ln (1 - 0.01) = ln (0.01) : n = \frac{ln ( 0.01 )}{ln ( 0.99 )}

n = \frac{ln ( 0.01 )}{ln ( 0.99 )}

4 \cdot 5^{x} - 3 = 7

8 1^{x} = \frac{1}{27}

8^{5 - x} = 3

2^{3 x - 4} = 11

1 6^{t - 0.25} = \frac{1 6 ^{t}}{2}

What is the answer to solvefor n,(1-0.01)^n=0.01 ?
The answer to solvefor n,(1-0.01)^n=0.01 is n=(ln(0.01))/(ln(0.99))