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Popular >

solvefor x,2^x-2^y=1

Solution

solve for

x, 2^{x} - 2^{y} = 1

Solution

x = \frac{ln ( 1 + 2 ^{y} )}{ln ( 2 )}

Solution steps

2^{x} - 2^{y} = 1

Move

2^{y}

to the right side

2^{x} = 1 + 2^{y}

Apply exponent rules

x ln (2) = ln (1 + 2^{y})

Solve

x ln (2) = ln (1 + 2^{y}) : x = \frac{ln ( 1 + 2 ^{y} )}{ln ( 2 )}

x = \frac{ln ( 1 + 2 ^{y} )}{ln ( 2 )}

Popular Examples

220 = 2^{x}

solvefor x,1=e^{2x-3}-5 solve for

x, 1 = e^{2 x - 3} - 5

5=5+16e^{k(34)}

5 = 5 + 16 e^{k (34)}

(\frac{1}{8})^{x} = 512

\frac{- e ^{x} + 2}{3} = 0

Frequently Asked Questions (FAQ)

What is the answer to solvefor x,2^x-2^y=1 ?
The answer to solvefor x,2^x-2^y=1 is x=(ln(1+2^y))/(ln(2))