What is the answer to 2^{x^2-4x-12}=8^{x+2} ?

The answer to 2^{x^2-4x-12}=8^{x+2} is x=9,x=-2

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2^{x^2-4x-12}=8^{x+2}

2^{x^{2} - 4 x - 12} = 8^{x + 2}

x = 9, x = - 2

Solution steps

2^{x^{2} - 4 x - 12} = 8^{x + 2}

Apply exponent rules

x^{2} - 4 x - 12 = 3 (x + 2)

Solve

x^{2} - 4 x - 12 = 3 (x + 2) : x = 9, x = - 2

x = 9, x = - 2

12 1^{2 x} = 1 1^{x + 3}

x, 3^{3 x - 2} = 9^{x}

a, 2^{a} = 3^{b}

5^{2 x} - 5^{x} - 6 = 0

2 5^{x} = 5^{x} + 6

What is the answer to 2^{x^2-4x-12}=8^{x+2} ?
The answer to 2^{x^2-4x-12}=8^{x+2} is x=9,x=-2
Solve for x: 2^{x^2-4x-12}=8^{x+2}
The solution is x=9,x=-2