What is the answer to 3^{3+x}=7 ?

The answer to 3^{3+x}=7 is x=(ln(7))/(ln(3))-3

Solve for x: 3^{3+x}=7

The solution is x=(ln(7))/(ln(3))-3

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3^{3 + x} = 7

x = \frac{ln ( 7 )}{ln ( 3 )} - 3

Decimal Notation

x = - 1.22875 \dots

Solution steps

3^{3 + x} = 7

Apply exponent rules

(3 + x) ln (3) = ln (7)

Solve

(3 + x) ln (3) = ln (7) : x = \frac{ln ( 7 )}{ln ( 3 )} - 3

x = \frac{ln ( 7 )}{ln ( 3 )} - 3

- 2 = \frac{2 π}{( e ^{- c} + 1 )}

8 1^{x} = 63

4^{- 2 x - 1} = 16

3^{(- x + 1)} = \frac{1}{81}

e^{2 z} + e^{z} + 1 = 0

What is the answer to 3^{3+x}=7 ?
The answer to 3^{3+x}=7 is x=(ln(7))/(ln(3))-3
Solve for x: 3^{3+x}=7
The solution is x=(ln(7))/(ln(3))-3