What is the answer to (2^x)(4^{x+1})=8 ?

The answer to (2^x)(4^{x+1})=8 is x= 1/3

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(2^x)(4^{x+1})=8

(2^{x}) (4^{x + 1}) = 8

x = \frac{1}{3}

Decimal Notation

x = 0.33333 \dots

Solution steps

(2^{x}) (4^{x + 1}) = 8

Apply exponent rules

3 x = 1

Solve

3 x = 1 : x = \frac{1}{3}

x = \frac{1}{3}

7^{x + 3} = 4 9^{x + 3}

5^{3 x - 7} = 25

2 5^{(x + 2)} = 1

1 0^{x^{2} - 4} = 1

2 7^{1 - x} = (\frac{1}{9})^{2 - x}

What is the answer to (2^x)(4^{x+1})=8 ?
The answer to (2^x)(4^{x+1})=8 is x= 1/3
Solve for x: (2^x)(4^{x+1})=8
The solution is x= 1/3