What is the answer to 27^{1-x}=(1/9)^{2-x} ?

The answer to 27^{1-x}=(1/9)^{2-x} is x= 7/5

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

27^{1-x}=(1/9)^{2-x}

2 7^{1 - x} = (\frac{1}{9})^{2 - x}

x = \frac{7}{5}

Decimal Notation

x = 1.4

Solution steps

2 7^{1 - x} = (\frac{1}{9})^{2 - x}

Apply exponent rules

3 (1 - x) = - 2 (2 - x)

Solve

3 (1 - x) = - 2 (2 - x) : x = \frac{7}{5}

x = \frac{7}{5}

3500 (1 + 0.25)^{- n} = 500

x, y = e^{k x}

4^{2 x - 1} = 1024

5^{5 x - 4} = 35

4^{x + 1} = 2 - 7 (2^{x})

What is the answer to 27^{1-x}=(1/9)^{2-x} ?
The answer to 27^{1-x}=(1/9)^{2-x} is x= 7/5
Solve for x: 27^{1-x}=(1/9)^{2-x}
The solution is x= 7/5