What is the answer to solvefor t,3Q=Qe^{0.02t} ?

The answer to solvefor t,3Q=Qe^{0.02t} is t=(ln(3))/(0.02)

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solvefor t,3Q=Qe^{0.02t}

solve for

t, 3 Q = Q e^{0.02 t}

t = \frac{ln ( 3 )}{0.02}

Decimal Notation

t = 54.93061 \dots

Solution steps

3 Q = Q e^{0.02 t}

Switch sides

Q e^{0.02 t} = 3 Q

Divide both sides by

Q

e^{0.02 t} = 3

Apply exponent rules

0.02 t = ln (3)

Solve

0.02 t = ln (3) : t = \frac{ln ( 3 )}{0.02}

t = \frac{ln ( 3 )}{0.02}

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1 2^{2 x} = 8.3 6^{x}

(2^{1 - x^{2}}) = \frac{1}{8}

2^{x} - 6 (2^{- x}) = 6

What is the answer to solvefor t,3Q=Qe^{0.02t} ?
The answer to solvefor t,3Q=Qe^{0.02t} is t=(ln(3))/(0.02)