What is the answer to (2^{1-x^2})= 1/8 ?

The answer to (2^{1-x^2})= 1/8 is x=2,x=-2

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(2^{1-x^2})= 1/8

(2^{1 - x^{2}}) = \frac{1}{8}

x = 2, x = - 2

Solution steps

(2^{1 - x^{2}}) = \frac{1}{8}

Apply exponent rules

1 - x^{2} = - 3

Solve

1 - x^{2} = - 3 : x = 2, x = - 2

x = 2, x = - 2

2^{x} - 6 (2^{- x}) = 6

2^{x^{2}} - 8^{2 x + 9} = 0

2 7^{2 x + 3} = 9^{\frac{x}{5}}

e^{x - 1} - 1.5 x = 0

(\frac{1}{100})^{2 x} = 1

What is the answer to (2^{1-x^2})= 1/8 ?
The answer to (2^{1-x^2})= 1/8 is x=2,x=-2
Solve for x: (2^{1-x^2})= 1/8
The solution is x=2,x=-2