What is the answer to 2^{x^2}-8^{2x+9}=0 ?

The answer to 2^{x^2}-8^{2x+9}=0 is x=9,x=-3

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2^{x^2}-8^{2x+9}=0

2^{x^{2}} - 8^{2 x + 9} = 0

x = 9, x = - 3

Solution steps

2^{x^{2}} - 8^{2 x + 9} = 0

Add

8^{2 x + 9}

to both sides

2^{x^{2}} - 8^{2 x + 9} + 8^{2 x + 9} = 0 + 8^{2 x + 9}

Simplify

2^{x^{2}} = 8^{2 x + 9}

Apply exponent rules

x^{2} = 3 (2 x + 9)

Solve

x^{2} = 3 (2 x + 9) : x = 9, x = - 3

x = 9, x = - 3

2 7^{2 x + 3} = 9^{\frac{x}{5}}

e^{x - 1} - 1.5 x = 0

(\frac{1}{100})^{2 x} = 1

e^{x} - 4 e^{- x} = 3

What is the answer to 2^{x^2}-8^{2x+9}=0 ?
The answer to 2^{x^2}-8^{2x+9}=0 is x=9,x=-3
Solve for x: 2^{x^2}-8^{2x+9}=0
The solution is x=9,x=-3