What is the answer to 10^{(x^2-1)/(x+1)}=10 ?

The answer to 10^{(x^2-1)/(x+1)}=10 is x=2

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10^{(x^2-1)/(x+1)}=10

1 0^{\frac{x ^{2} - 1}{x + 1}} = 10

x = 2

Solution steps

1 0^{\frac{x ^{2} - 1}{x + 1}} = 10

Apply exponent rules

x - 1 = 1

Solve

x - 1 = 1 : x = 2

x = 2

3^{2 - 5 x} = 8 (9^{x - 1})

e^{2 x} - e^{x} - 132 = 0

83 = 1 1^{x}

15000 = 2370.56 e^{0.04 x}

2^{5 x - 3} = 14

What is the answer to 10^{(x^2-1)/(x+1)}=10 ?
The answer to 10^{(x^2-1)/(x+1)}=10 is x=2
Solve for x: 10^{(x^2-1)/(x+1)}=10
The solution is x=2