What is the answer to solvefor x,5(1.2)^{x-1}=4 ?

The answer to solvefor x,5(1.2)^{x-1}=4 is x=(ln(4/5))/(ln(1.2))+1

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solvefor x,5(1.2)^{x-1}=4

solve for

x, 5 (1.2)^{x - 1} = 4

x = \frac{ln ( \frac{4}{5} )}{ln ( 1.2 )} + 1

Decimal Notation

x = - 0.22390 \dots

Solution steps

5 (1.2)^{x - 1} = 4

Divide both sides by

5

1. 2^{x - 1} = \frac{4}{5}

Apply exponent rules

(x - 1) ln (1.2) = ln (\frac{4}{5})

Solve

(x - 1) ln (1.2) = ln (\frac{4}{5}) : x = \frac{ln ( \frac{4}{5} )}{ln ( 1.2 )} + 1

x = \frac{ln ( \frac{4}{5} )}{ln ( 1.2 )} + 1

3^{2 7^{x - 2}} = 9^{9^{x + 1}}

2 = (\frac{1}{4})^{x}

57 = 5 e^{0.02 \cdot x}

100 0^{x} = 0.1

x, z = e^{\frac{y}{x}}

What is the answer to solvefor x,5(1.2)^{x-1}=4 ?
The answer to solvefor x,5(1.2)^{x-1}=4 is x=(ln(4/5))/(ln(1.2))+1