What is the answer to 3^x+1-2=25 ?

The answer to 3^x+1-2=25 is x=(ln(26))/(ln(3))

Solve for x: 3^x+1-2=25

The solution is x=(ln(26))/(ln(3))

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3^{x} + 1 - 2 = 25

x = \frac{ln ( 26 )}{ln ( 3 )}

Decimal Notation

x = 2.96564 \dots

Solution steps

3^{x} + 1 - 2 = 25

Add/Subtract the numbers:

1 - 2 = - 1

3^{x} - 1 = 25

Move

1

to the right side

3^{x} = 26

Apply exponent rules

x ln (3) = ln (26)

Solve

x ln (3) = ln (26) : x = \frac{ln ( 26 )}{ln ( 3 )}

x = \frac{ln ( 26 )}{ln ( 3 )}

0. 2^{x + 1} = 0.6

135 = 20 + 1130 e^{30 k}

2^{x} + 2^{4 - x} = 17

2^{x^{2} - 2 x + 3} = 4

x^{x} = (x)^{x}

What is the answer to 3^x+1-2=25 ?
The answer to 3^x+1-2=25 is x=(ln(26))/(ln(3))
Solve for x: 3^x+1-2=25
The solution is x=(ln(26))/(ln(3))