What is the answer to 67=21^x ?

The answer to 67=21^x is x=(ln(67))/(ln(21))

The solution is x=(ln(67))/(ln(21))

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67=21^x

67 = 2 1^{x}

x = \frac{ln ( 67 )}{ln ( 21 )}

Decimal Notation

x = 1.38106 \dots

Solution steps

67 = 2 1^{x}

Apply exponent rules

ln (67) = x ln (21)

Solve

ln (67) = x ln (21) : x = \frac{ln ( 67 )}{ln ( 21 )}

x = \frac{ln ( 67 )}{ln ( 21 )}

y = b + a e^{- x}, x

x, e^{x^{2} + 1} = 5 e^{- x}

4^{3 x - 15} - 64 = 0

2^{x^{2}} = 8

64 = 3 2^{- x + 2}