What is the answer to 27^{x+3}=(3^{2x-1})(9^{x+2}) ?

The answer to 27^{x+3}=(3^{2x-1})(9^{x+2}) is x=6

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27^{x+3}=(3^{2x-1})(9^{x+2})

2 7^{x + 3} = (3^{2 x - 1}) (9^{x + 2})

x = 6

Solution steps

2 7^{x + 3} = (3^{2 x - 1}) (9^{x + 2})

Apply exponent rules

3 (x + 3) = 2 x - 1 + 2 (x + 2)

Solve

3 (x + 3) = 2 x - 1 + 2 (x + 2) : x = 6

x = 6

98415 = 5 \cdot 3^{n - 1}

2^{x - 1} = 3^{2 x - 1}

y, (\frac{1}{2})^{y} = x

1 6^{x} - 5 \cdot 4^{x} = 24

3^{2 c + 1} = 28 \cdot 3^{c} - 9

What is the answer to 27^{x+3}=(3^{2x-1})(9^{x+2}) ?
The answer to 27^{x+3}=(3^{2x-1})(9^{x+2}) is x=6
Solve for x: 27^{x+3}=(3^{2x-1})(9^{x+2})
The solution is x=6