What is the answer to 7^{2+x}=98 ?

The answer to 7^{2+x}=98 is x=(ln(98))/(ln(7))-2

Solve for x: 7^{2+x}=98

The solution is x=(ln(98))/(ln(7))-2

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7^{2 + x} = 98

x = \frac{ln ( 98 )}{ln ( 7 )} - 2

Decimal Notation

x = 0.35620 \dots

Solution steps

7^{2 + x} = 98

Apply exponent rules

(2 + x) ln (7) = ln (98)

Solve

(2 + x) ln (7) = ln (98) : x = \frac{ln ( 98 )}{ln ( 7 )} - 2

x = \frac{ln ( 98 )}{ln ( 7 )} - 2

2^{x^{3}} = 12 8^{x}

4 e^{2 x} + 3 e^{x} = 1

6^{2 x - 1} + 180 = 6^{2 x}

3^{x + 2} = 3^{2 x - 5}

2 (2^{2 x}) + 4 = 9 (2^{x})

What is the answer to 7^{2+x}=98 ?
The answer to 7^{2+x}=98 is x=(ln(98))/(ln(7))-2
Solve for x: 7^{2+x}=98
The solution is x=(ln(98))/(ln(7))-2