What is the answer to 3^{(x^2+4x)}= 1/27 ?

The answer to 3^{(x^2+4x)}= 1/27 is x=-1,x=-3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

3^{(x^2+4x)}= 1/27

3^{(x^{2} + 4 x)} = \frac{1}{27}

x = - 1, x = - 3

Solution steps

3^{(x^{2} + 4 x)} = \frac{1}{27}

Apply exponent rules

x^{2} + 4 x = - 3

Solve

x^{2} + 4 x = - 3 : x = - 1, x = - 3

x = - 1, x = - 3

4^{2 x - 1} = 5^{x + 2}

e^{(2 x)} - 2 e^{(x)} - 24 = 0

25 6^{- 1} = 1 6^{2 x - 2}

x, 2^{x} 3^{y} = 6

3 \cdot 5^{2 t - 1} = 75

What is the answer to 3^{(x^2+4x)}= 1/27 ?
The answer to 3^{(x^2+4x)}= 1/27 is x=-1,x=-3
Solve for x: 3^{(x^2+4x)}= 1/27
The solution is x=-1,x=-3