What is the answer to 256^{-1}=16^{2x-2} ?

The answer to 256^{-1}=16^{2x-2} is x=0

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256^{-1}=16^{2x-2}

25 6^{- 1} = 1 6^{2 x - 2}

x = 0

Solution steps

25 6^{- 1} = 1 6^{2 x - 2}

Apply exponent rules

- 2 = 2 x - 2

Solve

- 2 = 2 x - 2 : x = 0

x = 0

x, 2^{x} 3^{y} = 6

3 \cdot 5^{2 t - 1} = 75

4 \cdot 2^{- \frac{t}{5}} = 288

77 = 1 1^{x}

y, e^{x + y} = x

What is the answer to 256^{-1}=16^{2x-2} ?
The answer to 256^{-1}=16^{2x-2} is x=0
Solve for x: 256^{-1}=16^{2x-2}
The solution is x=0