What is the answer to 8^x=(sqrt(2))^{2x^2+4} ?

The answer to 8^x=(sqrt(2))^{2x^2+4} is x=2,x=1

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8^x=(sqrt(2))^{2x^2+4}

8^{x} = (2)^{2 x^{2} + 4}

x = 2, x = 1

Solution steps

8^{x} = (2)^{2 x^{2} + 4}

Apply exponent rules

3 x = x^{2} + 2

Solve

3 x = x^{2} + 2 : x = 2, x = 1

x = 2, x = 1

x, y^{1} = e^{x}

20 \cdot 2^{x} = 5 \cdot 3^{x}

25 e^{10 k} = 50

380 = 760 \cdot e^{(- 144) \cdot x}

t, x = e^{t} - 1

What is the answer to 8^x=(sqrt(2))^{2x^2+4} ?
The answer to 8^x=(sqrt(2))^{2x^2+4} is x=2,x=1
Solve for x: 8^x=(sqrt(2))^{2x^2+4}
The solution is x=2,x=1