What is the answer to 9^{x+4}=27^{5x-2} ?

The answer to 9^{x+4}=27^{5x-2} is x= 14/13

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9^{x+4}=27^{5x-2}

9^{x + 4} = 2 7^{5 x - 2}

x = \frac{14}{13}

Decimal Notation

x = 1.07692 \dots

Solution steps

9^{x + 4} = 2 7^{5 x - 2}

Apply exponent rules

2 (x + 4) = 3 (5 x - 2)

Solve

2 (x + 4) = 3 (5 x - 2) : x = \frac{14}{13}

x = \frac{14}{13}

3 e^{5 x} = 8943

2^{2 x} \cdot 2 = 3^{x} \cdot 3^{3}

7^{2 x} = 7^{x - 3}

1000000 = 27000 \cdot 131 2^{x}

1 0^{4 x - 8} = 6^{10 x + 3}

What is the answer to 9^{x+4}=27^{5x-2} ?
The answer to 9^{x+4}=27^{5x-2} is x= 14/13
Solve for x: 9^{x+4}=27^{5x-2}
The solution is x= 14/13