What is the answer to 2^{2x}*2=3^x*3^3 ?

The answer to 2^{2x}*2=3^x*3^3 is x=(3ln(3)-ln(2))/(2ln(2)-ln(3))

Solve for x: 2^{2x}*2=3^x*3^3

The solution is x=(3ln(3)-ln(2))/(2ln(2)-ln(3))

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2^{2 x} \cdot 2 = 3^{x} \cdot 3^{3}

x = \frac{3 ln ( 3 ) - ln ( 2 )}{2 ln ( 2 ) - ln ( 3 )}

Decimal Notation

x = 9.04710 \dots

Solution steps

2^{2 x} \cdot 2 = 3^{x} \cdot 3^{3}

Apply exponent rules

(2 x + 1) ln (2) = (x + 3) ln (3)

Solve

(2 x + 1) ln (2) = (x + 3) ln (3) : x = \frac{3 ln ( 3 ) - ln ( 2 )}{2 ln ( 2 ) - ln ( 3 )}

x = \frac{3 ln ( 3 ) - ln ( 2 )}{2 ln ( 2 ) - ln ( 3 )}

7^{2 x} = 7^{x - 3}

1000000 = 27000 \cdot 131 2^{x}

1 0^{4 x - 8} = 6^{10 x + 3}

3^{x + 2} = 18

1.1 2^{x} = 2

What is the answer to 2^{2x}*2=3^x*3^3 ?
The answer to 2^{2x}*2=3^x*3^3 is x=(3ln(3)-ln(2))/(2ln(2)-ln(3))
Solve for x: 2^{2x}*2=3^x*3^3
The solution is x=(3ln(3)-ln(2))/(2ln(2)-ln(3))