What is the answer to 2^{2x-1}=4^{3x+2} ?

The answer to 2^{2x-1}=4^{3x+2} is x=-5/4

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2^{2x-1}=4^{3x+2}

2^{2 x - 1} = 4^{3 x + 2}

x = - \frac{5}{4}

Decimal Notation

x = - 1.25

Solution steps

2^{2 x - 1} = 4^{3 x + 2}

Apply exponent rules

2 x - 1 = 2 (3 x + 2)

Solve

2 x - 1 = 2 (3 x + 2) : x = - \frac{5}{4}

x = - \frac{5}{4}

7^{(x + 2)} = 98

x, e^{x} - y = 0

1 6^{x + 2} = \frac{1}{4}

(x - 2)^{x^{2} - 2 x} = (x - 2)^{x + 4}

7^{5 x - 4} = 14

What is the answer to 2^{2x-1}=4^{3x+2} ?
The answer to 2^{2x-1}=4^{3x+2} is x=-5/4
Solve for x: 2^{2x-1}=4^{3x+2}
The solution is x=-5/4