What is the answer to solvefor a,ln(x^{(2-a)})=4 ?

The answer to solvefor a,ln(x^{(2-a)})=4 is a=-(4-2ln(x))/(ln(x))

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solvefor a,ln(x^{(2-a)})=4

solve for

a, ln (x^{(2 - a)}) = 4

a = - \frac{4 - 2 ln ( x )}{ln ( x )}

Solution steps

ln (x^{(2 - a)}) = 4

Rewrite the equation with

x^{2 - a} = u

ln (u) = 4

Solve

ln (u) = 4 : u = e^{4}

u = e^{4}

Substitute back

u = x^{2 - a},

solve for

a

Solve

x^{2 - a} = e^{4} : a = - \frac{4 - 2 ln ( x )}{ln ( x )}

a = - \frac{4 - 2 ln ( x )}{ln ( x )}

3^{n} = 81

4^{x + 2} = 1 6^{2 x - 4}

5^{- 2 x + 1} = 2 5^{x - 2}

4^{x + 1} = 5^{x}

5^{2 x} = 3^{3 x + 1}

What is the answer to solvefor a,ln(x^{(2-a)})=4 ?
The answer to solvefor a,ln(x^{(2-a)})=4 is a=-(4-2ln(x))/(ln(x))