What is the answer to 2^{x+1}*2^{3x+2}=4^{4x+3} ?

The answer to 2^{x+1}*2^{3x+2}=4^{4x+3} is x=-3/4

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2^{x+1}*2^{3x+2}=4^{4x+3}

2^{x + 1} \cdot 2^{3 x + 2} = 4^{4 x + 3}

x = - \frac{3}{4}

Decimal Notation

x = - 0.75

Solution steps

2^{x + 1} \cdot 2^{3 x + 2} = 4^{4 x + 3}

Apply exponent rules

4 x + 3 = 2 (4 x + 3)

Solve

4 x + 3 = 2 (4 x + 3) : x = - \frac{3}{4}

x = - \frac{3}{4}

1 1^{x - 5} = 7^{x - 5}

3^{n + 1} + 3^{n + 2} + 3^{n + 3} = 351

0 = e^{2 x} - 4

3 \cdot 4^{x} = 21

7^{2 x} = 0.18

What is the answer to 2^{x+1}*2^{3x+2}=4^{4x+3} ?
The answer to 2^{x+1}*2^{3x+2}=4^{4x+3} is x=-3/4
Solve for x: 2^{x+1}*2^{3x+2}=4^{4x+3}
The solution is x=-3/4