What is the answer to 3^{n+1}+3^{n+2}+3^{n+3}=351 ?

The answer to 3^{n+1}+3^{n+2}+3^{n+3}=351 is n=2

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3^{n+1}+3^{n+2}+3^{n+3}=351

3^{n + 1} + 3^{n + 2} + 3^{n + 3} = 351

n = 2

Solution steps

3^{n + 1} + 3^{n + 2} + 3^{n + 3} = 351

Factor

3^{n + 1} + 3^{n + 2} + 3^{n + 3} : 13 \cdot 3^{1 + n}

13 \cdot 3^{1 + n} = 351

Divide both sides by

13

3^{1 + n} = 27

Apply exponent rules

1 + n = 3

Solve

1 + n = 3 : n = 2

n = 2

0 = e^{2 x} - 4

3 \cdot 4^{x} = 21

7^{2 x} = 0.18

3 e^{x + 2} = 12

2^{x} \cdot 3^{x + 1} = 10

What is the answer to 3^{n+1}+3^{n+2}+3^{n+3}=351 ?
The answer to 3^{n+1}+3^{n+2}+3^{n+3}=351 is n=2
Solve for n: 3^{n+1}+3^{n+2}+3^{n+3}=351
The solution is n=2