What is the answer to 5^{x+9}=9^x ?

The answer to 5^{x+9}=9^x is x=(9ln(5))/(2ln(3)-ln(5))

Solve for x: 5^{x+9}=9^x

The solution is x=(9ln(5))/(2ln(3)-ln(5))

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5^{x + 9} = 9^{x}

x = \frac{9 ln ( 5 )}{2 ln ( 3 ) - ln ( 5 )}

Decimal Notation

x = 24.64319 \dots

Solution steps

5^{x + 9} = 9^{x}

Apply exponent rules

(x + 9) ln (5) = x ln (9)

Solve

(x + 9) ln (5) = x ln (9) : x = \frac{9 ln ( 5 )}{2 ln ( 3 ) - ln ( 5 )}

x = \frac{9 ln ( 5 )}{2 ln ( 3 ) - ln ( 5 )}

4^{3 x - 1} = \frac{1}{( 8 ^{x - 1} )}

2^{w} = \frac{1}{28}

e^{4 x} + 2 e^{2 x} + 1 = 0

21 = 0.2497 e^{1.2073 x}

g (n) = 7^{n}, g (2)

What is the answer to 5^{x+9}=9^x ?
The answer to 5^{x+9}=9^x is x=(9ln(5))/(2ln(3)-ln(5))
Solve for x: 5^{x+9}=9^x
The solution is x=(9ln(5))/(2ln(3)-ln(5))