What is the answer to 3*2^x=15-2^{x+1} ?

The answer to 3*2^x=15-2^{x+1} is x=(ln(3))/(ln(2))

Solve for x: 3*2^x=15-2^{x+1}

The solution is x=(ln(3))/(ln(2))

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3 \cdot 2^{x} = 15 - 2^{x + 1}

x = \frac{ln ( 3 )}{ln ( 2 )}

Decimal Notation

x = 1.58496 \dots

Solution steps

3 \cdot 2^{x} = 15 - 2^{x + 1}

Add

2^{x + 1}

to both sides

3 \cdot 2^{x} + 2^{x + 1} = 15 - 2^{x + 1} + 2^{x + 1}

Simplify

3 \cdot 2^{x} + 2^{x + 1} = 15

Factor

3 \cdot 2^{x} + 2^{x + 1} : 5 \cdot 2^{x}

5 \cdot 2^{x} = 15

Divide both sides by

5

2^{x} = 3

Apply exponent rules

x ln (2) = ln (3)

Solve

x ln (2) = ln (3) : x = \frac{ln ( 3 )}{ln ( 2 )}

x = \frac{ln ( 3 )}{ln ( 2 )}

e^{4 x} = 5

4^{2 x + 1} = (0.5)^{3 x + 2}

2^{3 x} \cdot 4^{x + 1} = 64

0.0625 = 0. 5^{x}

20 e^{8 k} = 60

What is the answer to 3*2^x=15-2^{x+1} ?
The answer to 3*2^x=15-2^{x+1} is x=(ln(3))/(ln(2))
Solve for x: 3*2^x=15-2^{x+1}
The solution is x=(ln(3))/(ln(2))