What is the answer to 0=(-28)/(2^{5x+5)}+7 ?

The answer to 0=(-28)/(2^{5x+5)}+7 is x=-3/5

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0=(-28)/(2^{5x+5)}+7

0 = \frac{- 28}{2 ^{5 x + 5}} + 7

x = - \frac{3}{5}

Decimal Notation

x = - 0.6

Solution steps

0 = \frac{- 28}{2 ^{5 x + 5}} + 7

Apply exponent rules

0 = - 28 \cdot 2^{- 5 x - 5} + 7

Add

28 2^{- 5 x - 5}

to both sides

0 + 28 \cdot 2^{- 5 x - 5} = - 28 \cdot 2^{- 5 x - 5} + 7 + 28 \cdot 2^{- 5 x - 5}

Simplify

28 \cdot 2^{- 5 x - 5} = 7

Divide both sides by

28

2^{- 5 x - 5} = \frac{1}{4}

Apply exponent rules

- 5 x - 5 = - 2

Solve

- 5 x - 5 = - 2 : x = - \frac{3}{5}

x = - \frac{3}{5}

Verify Solutions:

x = - \frac{3}{5}

True

The solution is

x = - \frac{3}{5}

8 e^{x} - 5 = 0

2^{2 x + 1} - 4 = 2^{x + 1}

6 4^{x} - 4 = 0

10 = 4^{x}

8^{x + 1} \cdot 4^{7 x} = 1 6^{2 x - 3}

What is the answer to 0=(-28)/(2^{5x+5)}+7 ?
The answer to 0=(-28)/(2^{5x+5)}+7 is x=-3/5
Solve for x: 0=(-28)/(2^{5x+5)}+7
The solution is x=-3/5