What is the answer to 2^x=(sqrt(2))/2 ?

The answer to 2^x=(sqrt(2))/2 is x=-1/2

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2^x=(sqrt(2))/2

2^{x} = \frac{2}{2}

x = - \frac{1}{2}

Decimal Notation

x = - 0.5

Solution steps

2^{x} = \frac{2}{2}

Apply exponent rules

x = - \frac{1}{2}

17 = 2^{n}

1 0^{5} = (1 0^{- 13}) (1 0^{x})

3^{x + 1} + 3^{x - 1} + 3^{x} = 351

- 2 e^{- x} = 3 e^{x} - 5

1 - x = e^{x}