What is the answer to 17=2^n ?

The answer to 17=2^n is n=(ln(17))/(ln(2))

The solution is n=(ln(17))/(ln(2))

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17=2^n

17 = 2^{n}

n = \frac{ln ( 17 )}{ln ( 2 )}

Decimal Notation

n = 4.08746 \dots

Solution steps

17 = 2^{n}

Apply exponent rules

ln (17) = n ln (2)

Solve

ln (17) = n ln (2) : n = \frac{ln ( 17 )}{ln ( 2 )}

n = \frac{ln ( 17 )}{ln ( 2 )}

1 0^{5} = (1 0^{- 13}) (1 0^{x})

3^{x + 1} + 3^{x - 1} + 3^{x} = 351

- 2 e^{- x} = 3 e^{x} - 5

1 - x = e^{x}

2^{x} + 2^{x + 2} + 2^{x + 3} = 208