What is the answer to (sqrt(2))^{x+2}=(0.5)^{2x-4} ?

The answer to (sqrt(2))^{x+2}=(0.5)^{2x-4} is x= 6/5

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(sqrt(2))^{x+2}=(0.5)^{2x-4}

(2)^{x + 2} = (0.5)^{2 x - 4}

x = \frac{6}{5}

Decimal Notation

x = 1.2

Solution steps

(2)^{x + 2} = (0.5)^{2 x - 4}

Apply exponent rules

\frac{1}{2} (x + 2) = - (2 x - 4)

Solve

\frac{1}{2} (x + 2) = - (2 x - 4) : x = \frac{6}{5}

x = \frac{6}{5}

100 = e^{- 9 t + 3 l n (2)}

5^{x} = e^{x - 1}

x^{l o g_{5} (x) - 2} = 125

5^{4 X + 20} = 5^{12 X + 20}

4^{- x + 4} = 5^{9 x}

What is the answer to (sqrt(2))^{x+2}=(0.5)^{2x-4} ?
The answer to (sqrt(2))^{x+2}=(0.5)^{2x-4} is x= 6/5
Solve for x: (sqrt(2))^{x+2}=(0.5)^{2x-4}
The solution is x= 6/5