What is the answer to 8^{2+x^2}=10^2 ?

The answer to 8^{2+x^2}=10^2 is x=sqrt((2ln(10))/(3ln(2))-2),x=-sqrt((2ln(10))/(3ln(2))-2)

Solve for x: 8^{2+x^2}=10^2

The solution is x=sqrt((2ln(10))/(3ln(2))-2),x=-sqrt((2ln(10))/(3ln(2))-2)

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8^{2 + x^{2}} = 1 0^{2}

x = \frac{2 ln ( 10 )}{3 ln ( 2 )} - 2, x = - \frac{2 ln ( 10 )}{3 ln ( 2 )} - 2

Decimal Notation

x = 0.46326 \dots, x = - 0.46326 \dots

Solution steps

8^{2 + x^{2}} = 1 0^{2}

Apply exponent rules

(2 + x^{2}) ln (8) = 2 ln (10)

Solve

(2 + x^{2}) ln (8) = 2 ln (10) : x = \frac{2 ln ( 10 )}{3 ln ( 2 )} - 2, x = - \frac{2 ln ( 10 )}{3 ln ( 2 )} - 2

x = \frac{2 ln ( 10 )}{3 ln ( 2 )} - 2, x = - \frac{2 ln ( 10 )}{3 ln ( 2 )} - 2

7^{x + 4} = 3

lo g_{27} (3^{x + 2}) = - 2

2^{2 x} - 6 \cdot 2^{x + 1} + 32 = 0

2 5^{x} - 5^{x + 1} + 4 = 0

9^{x} = 18

What is the answer to 8^{2+x^2}=10^2 ?
The answer to 8^{2+x^2}=10^2 is x=sqrt((2ln(10))/(3ln(2))-2),x=-sqrt((2ln(10))/(3ln(2))-2)
Solve for x: 8^{2+x^2}=10^2
The solution is x=sqrt((2ln(10))/(3ln(2))-2),x=-sqrt((2ln(10))/(3ln(2))-2)