What is the answer to log_{27}(3^{x+2})=-2 ?

The answer to log_{27}(3^{x+2})=-2 is x=-8

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log_{27}(3^{x+2})=-2

lo g_{27} (3^{x + 2}) = - 2

x = - 8

Solution steps

lo g_{27} (3^{x + 2}) = - 2

Rewrite the equation with

3^{x + 2} = u

lo g_{27} (u) = - 2

Solve

lo g_{27} (u) = - 2 : u = \frac{1}{729}

u = \frac{1}{729}

Substitute back

u = 3^{x + 2},

solve for

x

Solve

3^{x + 2} = \frac{1}{729} : x = - 8

x = - 8

2^{2 x} - 6 \cdot 2^{x + 1} + 32 = 0

2 5^{x} - 5^{x + 1} + 4 = 0

9^{x} = 18

5^{7 x + 5} = 3

4^{4^{n + 7}} = 2^{8^{n - 5}}

What is the answer to log_{27}(3^{x+2})=-2 ?
The answer to log_{27}(3^{x+2})=-2 is x=-8
Solve for x: log_{27}(3^{x+2})=-2
The solution is x=-8