What is the answer to 4^{4^{n+7}}=2^{8^{n-5}} ?

The answer to 4^{4^{n+7}}=2^{8^{n-5}} is n=30

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4^{4^{n+7}}=2^{8^{n-5}}

4^{4^{n + 7}} = 2^{8^{n - 5}}

n = 30

Solution steps

4^{4^{n + 7}} = 2^{8^{n - 5}}

Apply exponent rules

1 + 2 (n + 7) = 3 (n - 5)

Solve

1 + 2 (n + 7) = 3 (n - 5) : n = 30

n = 30

2^{n - 7} \cdot 5^{n - 4} = 1250

1 0^{\frac{2 x}{3}} = 15

3^{5 x (- 10)} = 1

x, 2 e^{x} + 3 e^{- 3 x} = 0

e^{2 t + 2} = 2 e^{2 - t}

What is the answer to 4^{4^{n+7}}=2^{8^{n-5}} ?
The answer to 4^{4^{n+7}}=2^{8^{n-5}} is n=30
Solve for n: 4^{4^{n+7}}=2^{8^{n-5}}
The solution is n=30