What is the answer to 2^{x+1}=44 ?

The answer to 2^{x+1}=44 is x=(ln(44))/(ln(2))-1

Solve for x: 2^{x+1}=44

The solution is x=(ln(44))/(ln(2))-1

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2^{x + 1} = 44

x = \frac{ln ( 44 )}{ln ( 2 )} - 1

Decimal Notation

x = 4.45943 \dots

Solution steps

2^{x + 1} = 44

Apply exponent rules

(x + 1) ln (2) = ln (44)

Solve

(x + 1) ln (2) = ln (44) : x = \frac{ln ( 44 )}{ln ( 2 )} - 1

x = \frac{ln ( 44 )}{ln ( 2 )} - 1

x e^{- x} + 2 e^{- x} = 0

6^{7 - x} = 6^{2 x + 1}

590 = 4230 (0.945)^{3 x - 4} + 70

e^{x} + x = 1

5^{2 x + 3} = 9^{x - 5}

What is the answer to 2^{x+1}=44 ?
The answer to 2^{x+1}=44 is x=(ln(44))/(ln(2))-1
Solve for x: 2^{x+1}=44
The solution is x=(ln(44))/(ln(2))-1