What is the answer to 9^{x-1}=36^x ?

The answer to 9^{x-1}=36^x is x=-(ln(3))/(ln(2))

Solve for x: 9^{x-1}=36^x

The solution is x=-(ln(3))/(ln(2))

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9^{x - 1} = 3 6^{x}

x = - \frac{ln ( 3 )}{ln ( 2 )}

Decimal Notation

x = - 1.58496 \dots

Solution steps

9^{x - 1} = 3 6^{x}

Apply exponent rules

(x - 1) ln (9) = x ln (36)

Solve

(x - 1) ln (9) = x ln (36) : x = - \frac{ln ( 3 )}{ln ( 2 )}

x = - \frac{ln ( 3 )}{ln ( 2 )}

90 e^{0.32 x} = 184.3613

lo g_{3} (3^{x}) = - 1

5^{2 x - 1} = 8^{x}

3^{x} = 6^{x - 1}

0.09 = 0. 5^{n}

What is the answer to 9^{x-1}=36^x ?
The answer to 9^{x-1}=36^x is x=-(ln(3))/(ln(2))
Solve for x: 9^{x-1}=36^x
The solution is x=-(ln(3))/(ln(2))