What is the answer to 5^{2x-1}=8^x ?

The answer to 5^{2x-1}=8^x is x=(ln(5))/(2ln(5)-3ln(2))

Solve for x: 5^{2x-1}=8^x

The solution is x=(ln(5))/(2ln(5)-3ln(2))

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5^{2 x - 1} = 8^{x}

x = \frac{ln ( 5 )}{2 ln ( 5 ) - 3 ln ( 2 )}

Decimal Notation

x = 1.41248 \dots

Solution steps

5^{2 x - 1} = 8^{x}

Apply exponent rules

(2 x - 1) ln (5) = x ln (8)

Solve

(2 x - 1) ln (5) = x ln (8) : x = \frac{ln ( 5 )}{2 ln ( 5 ) - 3 ln ( 2 )}

x = \frac{ln ( 5 )}{2 ln ( 5 ) - 3 ln ( 2 )}

3^{x} = 6^{x - 1}

0.09 = 0. 5^{n}

2^{x - 1} = 7

1 0^{2 x + 1} = 4 \cdot 1 0^{x}

2^{x} + 2^{x} = 4

What is the answer to 5^{2x-1}=8^x ?
The answer to 5^{2x-1}=8^x is x=(ln(5))/(2ln(5)-3ln(2))
Solve for x: 5^{2x-1}=8^x
The solution is x=(ln(5))/(2ln(5)-3ln(2))