What is the answer to 10^{2x+1}=4*10^x ?

The answer to 10^{2x+1}=4*10^x is x=(ln(2/5))/(ln(10))

Solve for x: 10^{2x+1}=4*10^x

The solution is x=(ln(2/5))/(ln(10))

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1 0^{2 x + 1} = 4 \cdot 1 0^{x}

x = \frac{ln ( \frac{2}{5} )}{ln ( 10 )}

Decimal Notation

x = - 0.39794 \dots

Solution steps

1 0^{2 x + 1} = 4 \cdot 1 0^{x}

Apply exponent rules

(2 x + 1) ln (10) = ln (4) + x ln (10)

Solve

(2 x + 1) ln (10) = ln (4) + x ln (10) : x = \frac{ln ( \frac{2}{5} )}{ln ( 10 )}

x = \frac{ln ( \frac{2}{5} )}{ln ( 10 )}

2^{x} + 2^{x} = 4

4^{5 - 3 x} = \frac{1}{8 ^{x + 1}}

4 \cdot 3^{x - 2} - 1 = 19

8^{n - 1} = 2

(x - 3)^{2 x - 4} = (x - 3)^{x + 3}

What is the answer to 10^{2x+1}=4*10^x ?
The answer to 10^{2x+1}=4*10^x is x=(ln(2/5))/(ln(10))
Solve for x: 10^{2x+1}=4*10^x
The solution is x=(ln(2/5))/(ln(10))