What is the answer to 4^{5-3x}= 1/(8^{x+1)} ?

The answer to 4^{5-3x}= 1/(8^{x+1)} is x= 13/3

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4^{5-3x}= 1/(8^{x+1)}

4^{5 - 3 x} = \frac{1}{8 ^{x + 1}}

x = \frac{13}{3}

Decimal Notation

x = 4.33333 \dots

Solution steps

4^{5 - 3 x} = \frac{1}{8 ^{x + 1}}

Apply exponent rules

2 (5 - 3 x) = 3 (- x - 1)

Solve

2 (5 - 3 x) = 3 (- x - 1) : x = \frac{13}{3}

x = \frac{13}{3}

Verify Solutions:

x = \frac{13}{3}

True

The solution is

x = \frac{13}{3}

4 \cdot 3^{x - 2} - 1 = 19

8^{n - 1} = 2

(x - 3)^{2 x - 4} = (x - 3)^{x + 3}

(0.1)^{2 x - 4} = 10

3^{30} = 2 7^{y}

What is the answer to 4^{5-3x}= 1/(8^{x+1)} ?
The answer to 4^{5-3x}= 1/(8^{x+1)} is x= 13/3
Solve for x: 4^{5-3x}= 1/(8^{x+1)}
The solution is x= 13/3