What is the answer to 4^{x-1}=(1/4)^{2x} ?

The answer to 4^{x-1}=(1/4)^{2x} is x= 1/3

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4^{x-1}=(1/4)^{2x}

4^{x - 1} = (\frac{1}{4})^{2 x}

x = \frac{1}{3}

Decimal Notation

x = 0.33333 \dots

Solution steps

4^{x - 1} = (\frac{1}{4})^{2 x}

Apply exponent rules

x - 1 = - 2 x

Solve

x - 1 = - 2 x : x = \frac{1}{3}

x = \frac{1}{3}

4^{4 x^{2}} = \frac{1}{1 6 ^{2 x - 3}}

\frac{4}{21} = e^{- 203 t}

2^{x} + 1 - \frac{3}{4} 2^{- x} = 0

9 \cdot 1 0^{x} - 81 = 0

(x + 2)^{3 x - 2} = (x + 2)^{x - 4}

What is the answer to 4^{x-1}=(1/4)^{2x} ?
The answer to 4^{x-1}=(1/4)^{2x} is x= 1/3
Solve for x: 4^{x-1}=(1/4)^{2x}
The solution is x= 1/3