What is the answer to 16^{x-1}=6^{4x} ?

The answer to 16^{x-1}=6^{4x} is x=-(ln(2))/(ln(3))

Solve for x: 16^{x-1}=6^{4x}

The solution is x=-(ln(2))/(ln(3))

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1 6^{x - 1} = 6^{4 x}

x = - \frac{ln ( 2 )}{ln ( 3 )}

Decimal Notation

x = - 0.63092 \dots

Solution steps

1 6^{x - 1} = 6^{4 x}

Apply exponent rules

(x - 1) ln (16) = 4 x ln (6)

Solve

(x - 1) ln (16) = 4 x ln (6) : x = - \frac{ln ( 2 )}{ln ( 3 )}

x = - \frac{ln ( 2 )}{ln ( 3 )}

2^{x^{2} - 4} = 128

8 \cdot 1 0^{n + 4} = 42

3^{2 x - 1} = 2100

10.5 = 15 (1 - e^{- (k) 40})

20 e^{2 x} - 40 e^{- x} = 0

What is the answer to 16^{x-1}=6^{4x} ?
The answer to 16^{x-1}=6^{4x} is x=-(ln(2))/(ln(3))
Solve for x: 16^{x-1}=6^{4x}
The solution is x=-(ln(2))/(ln(3))