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Popular >

7^{x+4}=pi^{2x}

Solution

7^{x + 4} = π^{2 x}

Solution

x = \frac{4 ln ( 7 )}{2 ln ( π ) - ln ( 7 )}

+1

Decimal Notation

x = 22.65652 \dots

Solution steps

7^{x + 4} = π^{2 x}

Apply exponent rules

(x + 4) ln (7) = 2 x ln (π)

Solve

(x + 4) ln (7) = 2 x ln (π) : x = \frac{4 ln ( 7 )}{2 ln ( π ) - ln ( 7 )}

x = \frac{4 ln ( 7 )}{2 ln ( π ) - ln ( 7 )}

Popular Examples

5^{3x+1}=5^{3x+2}-100

5^{3 x + 1} = 5^{3 x + 2} - 100

solvefor x,-f=2^x+1 solve for

x, - f = 2^{x} + 1

2^x+2^{x+2}= 9/2

2^{x} + 2^{x + 2} = \frac{9}{2}

(3^{3m})/(3^{m+1)}=243

\frac{3 ^{3 m}}{3 ^{m + 1}} = 243

6 (9^{x}) + 3^{x} - 2 = 0

Frequently Asked Questions (FAQ)

What is the answer to 7^{x+4}=pi^{2x} ?
The answer to 7^{x+4}=pi^{2x} is x=(4ln(7))/(2ln(pi)-ln(7))